#include<iostream>
using namespace std;

int get(string a)
{
    if(a=="Hunter")return 2;
    if(a=="Bear")return 1;
    return 0;
}
int main()
{
    int n;
    string a,b;
    cin>>n;
    while(n--)
    {

        cin>>a>>b;
        if(get(a)==(get(b)+1)%3) cout<<"Player2\n";
        else if(get(a)==get(b)) cout<<"Tie\n";
        else cout<<"Player1\n";
    }
    return 0;
}
//很有意思，照应题目的解法，简化了步骤，但是要注意不能写while(cin>>n,n--)

作者：CSQN
链接：https://www.acwing.com/activity/content/code/content/9790811/
来源：AcWing